A SeedAggregate Model
WikiMechanics describes the proton by starting with the archetypal chain of events
$\Psi \left( \sf{p^{+}} \right) = \left( \sf{\Omega}_{1}, \sf{\Omega}_{2}, \sf{\Omega}_{3} \ \ldots \ \right)$
where each repeated cycle $\sf{\Omega}$ is a bundle of 24 Anaxagorean sensations; four somatic perceptions on the rightside, eight on the left, four hot thermal feelings, four freezing, and finally four black visual sensations. The chain of events $\Psi$ is called a history of the proton. Each Anaxagorean sensation may be objectified to define a seed. And Aristotle refers^{1} to the primordial atomic mass as πανσπερμία or a seedaggregate. So to make a seedaggregate model for the proton we express $\sf{\Omega}$ as a bundle of seeds$\sf{\Omega} \left( \sf{p^{+}} \right) \leftrightarrow \mathrm{4}\sf{D} + \mathrm{4}\sf{B} + \mathrm{4}\sf{T} + \mathrm{4}\sf{O} + \mathrm{8}\overline{\sf{O}}$
A Quark Model of the Proton
Quarks are defined by pairs of seeds. So the seedaggregate model of the proton is further developed by associating seeds as


Then a proton is represented by a bundle of twelve quarks. And here is an iconic image of a proton.
$\sf{\Omega} \left( \sf{p^{+}} \right) \leftrightarrow \mathrm{2}\sf{d} + \mathrm{2}\bar{\sf{d}} + \mathrm{4}\sf{b} + \mathrm{4}\bar{ \sf{t} }$ 
Using these quarks, the mass of the proton is calculated to be 938.2720460 (MeV/c^{2}). This is exactly the same as the experimentally observed value because adjustable parameters like quark energies have been carefully chosen^{2} to get this result. For more mathematical detail, here are some spreadsheets.
A GroundState Proton Model
Quark coefficients are all integer multiples of two, and so the image above is drawn with the back row of quarks the same as the front. But we cannot have two identical quarks in the same bundle and still satisfy Pauli's exclusion principle. So the quark model is developed further with an additional requirement that the quarks in the front and back rows are out of phase with each other. That is, we suppose there is a difference in their relationship with the frame of reference that allows us to distinguish between them. This satisfies the definition for being in a groundstate and so the new arrangement is called a groundstate model of the proton. It can be expressed mathematically as
$\sf{\Omega} \left( \sf{p^{+}} \right) = \left\{ \mathcal{S}_{\LARGE{\circ}}, \mathcal{S}_{\LARGE{\bullet}} \right\}$
where
$\mathcal{S}_{\LARGE{\circ}} = \mathcal{S}_{\LARGE{\bullet}} \leftrightarrow \sf{d} + \bar{\sf{d}} + \mathrm{2}\sf{b} + \mathrm{2}\bar{ \sf{t} }$
And recall that $\delta_{ \theta}$ notes the phase so that
$\delta_{\theta} \left( \mathcal{S}_{\LARGE{\circ}} \right) = \delta_{\theta} \left( \mathcal{S}_{\LARGE{\bullet}} \right) = \pm 1$
To illustrate this model, we show quarks with a background that is dark or bright depending on their phase. Then the image above is made into a movie that uses shadows, horizons and background brightness to suggest a quark's relationship with the frameofreference.
Proton Stability
The thermodynamic temperature of a proton in its ground state is easily calculated from the quark average
$\begin{align} \it{T} \left( \sf{p^{+}} \right) &= \frac{1}{N} \sum T ^{\sf{q}} \\ &\ \\ &= \frac{1}{12} \left( 4 T ^{\sf{d}} + 4 T ^{\sf{b}} + 4 T ^{\sf{t}} \right) \\ &\ \\ &= \mathrm{2.7254885} \, \sf{(K)} \end{align}$
This is within experimental uncertainty of the observed^{3} value of 2.72548 ± 0.00057 (K) for the thermal black body spectrum of the microwave background radiation. It is common to describe this background radiation as 'cosmic', and to assert that it comes from a 'bigbang'. But seeing protons, bare naked in their groundstates, could offer another explanation. The proton temperature corresponds to a calculated mean life of 1.71 X 10^{55} seconds, which is consistent with the observed^{4} lower bound of 6.6 X 10^{36} seconds. So the proton is an extremely stable particle. This gives it a starring role in narratives connecting cause and effect.